96=-16x^2+112x

Solution for 96=-16x^2+112x equation:

96=-16x^2+112x

We move all terms to the left:

96-(-16x^2+112x)=0

We get rid of parentheses

16x^2-112x+96=0

a = 16; b = -112; c = +96;
Δ = b2-4ac
Δ = -1122-4·16·96
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-80}{2*16}=\frac{32}{32}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+80}{2*16}=\frac{192}{32}
=6
$